.04*k^2=1

Solution for .04*k^2=1 equation:

.04k^2=1

We move all terms to the left:

.04k^2-(1)=0

a = .04; b = 0; c = -1;
Δ = b2-4ac
Δ = 02-4·.04·(-1)
Δ = 0.16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{0.16}}{2*.04}=\frac{0-\sqrt{0.16}}{0.08}
=-\frac{\sqrt{}}{0.08}
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{0.16}}{2*.04}=\frac{0+\sqrt{0.16}}{0.08}
=\frac{\sqrt{}}{0.08}
$